;;; rtree.el --- functions for manipulating range trees ;; Copyright (C) 2010-2013 Free Software Foundation, Inc. ;; Author: Lars Magne Ingebrigtsen ;; This file is part of GNU Emacs. ;; GNU Emacs is free software: you can redistribute it and/or modify ;; it under the terms of the GNU General Public License as published by ;; the Free Software Foundation, either version 3 of the License, or ;; (at your option) any later version. ;; GNU Emacs is distributed in the hope that it will be useful, ;; but WITHOUT ANY WARRANTY; without even the implied warranty of ;; MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the ;; GNU General Public License for more details. ;; You should have received a copy of the GNU General Public License ;; along with GNU Emacs. If not, see . ;;; Commentary: ;; A "range tree" is a binary tree that stores ranges. They are ;; similar to interval trees, but do not allow overlapping intervals. ;; A range is an ordered list of number intervals, like this: ;; ((10 . 25) 56 78 (98 . 201)) ;; Common operations, like lookup, deletion and insertion are O(n) in ;; a range, but an rtree is O(log n) in all these operations. ;; Transformation between a range and an rtree is O(n). ;; The rtrees are quite simple. The structure of each node is ;; (cons (cons low high) (cons left right)) ;; That is, they are three cons cells, where the car of the top cell ;; is the actual range, and the cdr has the left and right child. The ;; rtrees aren't automatically balanced, but are balanced when ;; created, and can be rebalanced when deemed necessary. ;;; Code: (eval-when-compile (require 'cl)) (defmacro rtree-make-node () `(list (list nil) nil)) (defmacro rtree-set-left (node left) `(setcar (cdr ,node) ,left)) (defmacro rtree-set-right (node right) `(setcdr (cdr ,node) ,right)) (defmacro rtree-set-range (node range) `(setcar ,node ,range)) (defmacro rtree-low (node) `(caar ,node)) (defmacro rtree-high (node) `(cdar ,node)) (defmacro rtree-set-low (node number) `(setcar (car ,node) ,number)) (defmacro rtree-set-high (node number) `(setcdr (car ,node) ,number)) (defmacro rtree-left (node) `(cadr ,node)) (defmacro rtree-right (node) `(cddr ,node)) (defmacro rtree-range (node) `(car ,node)) (defsubst rtree-normalise-range (range) (when (numberp range) (setq range (cons range range))) range) (defun rtree-make (range) "Make an rtree from RANGE." ;; Normalize the range. (unless (listp (cdr-safe range)) (setq range (list range))) (rtree-make-1 (cons nil range) (length range))) (defun rtree-make-1 (range length) (let ((mid (/ length 2)) (node (rtree-make-node))) (when (> mid 0) (rtree-set-left node (rtree-make-1 range mid))) (rtree-set-range node (rtree-normalise-range (cadr range))) (setcdr range (cddr range)) (when (> (- length mid 1) 0) (rtree-set-right node (rtree-make-1 range (- length mid 1)))) node)) (defun rtree-memq (tree number) "Return non-nil if NUMBER is present in TREE." (while (and tree (not (and (>= number (rtree-low tree)) (<= number (rtree-high tree))))) (setq tree (if (< number (rtree-low tree)) (rtree-left tree) (rtree-right tree)))) tree) (defun rtree-add (tree number) "Add NUMBER to TREE." (while tree (cond ;; It's already present, so we don't have to do anything. ((and (>= number (rtree-low tree)) (<= number (rtree-high tree))) (setq tree nil)) ((< number (rtree-low tree)) (cond ;; Extend the low range. ((= number (1- (rtree-low tree))) (rtree-set-low tree number) ;; Check whether we need to merge this node with the child. (when (and (rtree-left tree) (= (rtree-high (rtree-left tree)) (1- number))) ;; Extend the range to the low from the child. (rtree-set-low tree (rtree-low (rtree-left tree))) ;; The child can't have a right child, so just transplant the ;; child's left tree to our left tree. (rtree-set-left tree (rtree-left (rtree-left tree)))) (setq tree nil)) ;; Descend further to the left. ((rtree-left tree) (setq tree (rtree-left tree))) ;; Add a new node. (t (let ((new-node (rtree-make-node))) (rtree-set-low new-node number) (rtree-set-high new-node number) (rtree-set-left tree new-node) (setq tree nil))))) (t (cond ;; Extend the high range. ((= number (1+ (rtree-high tree))) (rtree-set-high tree number) ;; Check whether we need to merge this node with the child. (when (and (rtree-right tree) (= (rtree-low (rtree-right tree)) (1+ number))) ;; Extend the range to the high from the child. (rtree-set-high tree (rtree-high (rtree-right tree))) ;; The child can't have a left child, so just transplant the ;; child's left right to our right tree. (rtree-set-right tree (rtree-right (rtree-right tree)))) (setq tree nil)) ;; Descend further to the right. ((rtree-right tree) (setq tree (rtree-right tree))) ;; Add a new node. (t (let ((new-node (rtree-make-node))) (rtree-set-low new-node number) (rtree-set-high new-node number) (rtree-set-right tree new-node) (setq tree nil)))))))) (defun rtree-delq (tree number) "Remove NUMBER from TREE destructively. Returns the new tree." (let ((result tree) prev) (while tree (cond ((< number (rtree-low tree)) (setq prev tree tree (rtree-left tree))) ((> number (rtree-high tree)) (setq prev tree tree (rtree-right tree))) ;; The number is in this node. (t (cond ;; The only entry; delete the node. ((= (rtree-low tree) (rtree-high tree)) (cond ;; Two children. Replace with successor value. ((and (rtree-left tree) (rtree-right tree)) (let ((parent tree) (successor (rtree-right tree))) (while (rtree-left successor) (setq parent successor successor (rtree-left successor))) ;; We now have the leftmost child of our right child. (rtree-set-range tree (rtree-range successor)) ;; Transplant the child (if any) to the parent. (rtree-set-left parent (rtree-right successor)))) (t (let ((rest (or (rtree-left tree) (rtree-right tree)))) ;; One or zero children. Remove the node. (cond ((null prev) (setq result rest)) ((eq (rtree-left prev) tree) (rtree-set-left prev rest)) (t (rtree-set-right prev rest))))))) ;; The lowest in the range; just adjust. ((= number (rtree-low tree)) (rtree-set-low tree (1+ number))) ;; The highest in the range; just adjust. ((= number (rtree-high tree)) (rtree-set-high tree (1- number))) ;; We have to split this range. (t (let ((new-node (rtree-make-node))) (rtree-set-low new-node (rtree-low tree)) (rtree-set-high new-node (1- number)) (rtree-set-low tree (1+ number)) (cond ;; Two children; insert the new node as the predecessor ;; node. ((and (rtree-left tree) (rtree-right tree)) (let ((predecessor (rtree-left tree))) (while (rtree-right predecessor) (setq predecessor (rtree-right predecessor))) (rtree-set-right predecessor new-node))) ((rtree-left tree) (rtree-set-right new-node tree) (rtree-set-left new-node (rtree-left tree)) (rtree-set-left tree nil) (cond ((null prev) (setq result new-node)) ((eq (rtree-left prev) tree) (rtree-set-left prev new-node)) (t (rtree-set-right prev new-node)))) (t (rtree-set-left tree new-node)))))) (setq tree nil)))) result)) (defun rtree-extract (tree) "Convert TREE to range form." (let (stack result) (while (or stack tree) (if tree (progn (push tree stack) (setq tree (rtree-right tree))) (setq tree (pop stack)) (push (if (= (rtree-low tree) (rtree-high tree)) (rtree-low tree) (rtree-range tree)) result) (setq tree (rtree-left tree)))) result)) (defun rtree-length (tree) "Return the number of numbers stored in TREE." (if (null tree) 0 (+ (rtree-length (rtree-left tree)) (1+ (- (rtree-high tree) (rtree-low tree))) (rtree-length (rtree-right tree))))) (provide 'rtree) ;;; rtree.el ends here